中航锂电研究院:2、证明:X(X+1)(X+2)(X+3)+1是完全平方
来源:百度文库 编辑:查人人中国名人网 时间:2024/05/23 23:12:23
另a=x2(平方)+3x
[(X+1)(X+2)]*[X(X+3)]+1
=(a+2)*a+1
=a2+2a+1
=(a+1)2(平方)
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!另a=2X(平方)+3x
[(X+1)(X+2)]*[X(X+3)]+1
=(a+2)*a+1
=a*a+2a+1
=(a+1)2(平方)
!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!楼上的错了
证明:原式=X(X+3) (X+1)(X+2) +1
=(X2+3X)(X2+3X+2)+1
=(X2+3X)2+2(X2+3X)+1
=(X2+3X+1)2
所以原式是完全平方
[(X+1)(X+2)]*[X(X+3)]+1
=(a+2)*a+1
=a2+2a+1
=(a+1)2(平方)
已知x^2-x-1=0,证明x^3=2x+1,x^5=5x+3
1+x+x^2+x^3=0 ,求x+x^2+x^3+...+x^2000
1+x+x(1+x)+x(1+x)2+x(1+x)3
1+x+x(1+x)+x(1+x)2+x(1+x)3
2、证明:X(X+1)(X+2)(X+3)+1是完全平方
证明:X(X+1)(X+2)(X+3)+1是完全平方
X*X-2X-1=0 求2x*x*x-3*x*x-4*x+2
解方程(x+1)(x+2)(x+3)(x+4)=(x+1)(x+1)+(x+2)(x+2)+(x+3)(x+3)+(x+4)(x+4)
(x+1)(x+2)(x+3)(x+4)=(x+1)(x+1)+(x+2)(x+2)+(x+3)(x+3)+(x+4)(x+4)
(1+x+x^2+X^3)^2-x^3