弋矶山医院口腔科:解方程(x+1)(x+2)(x+3)(x+4)=(x+1)(x+1)+(x+2)(x+2)+(x+3)(x+3)+(x+4)(x+4)

来源:百度文库 编辑:查人人中国名人网 时间:2024/04/27 05:28:52

这道题可以开出括号生算,也可用字母代换各项,用对称式解,具体的我就不列了。

在数学软件Matlab中输入命令:
syms x
solve('(x+1)*(x+2)*(x+3)*(x+4)=(x+1)*(x+1)+(x+2)*(x+2)+(x+3)*(x+3)+(x+4)*(x+4)')
得出结果:
ans =

-5/2-1/2*(13+4*15^(1/2))^(1/2)
-5/2+1/2*(13+4*15^(1/2))^(1/2)
-5/2-1/2*(13-4*15^(1/2))^(1/2)
-5/2+1/2*(13-4*15^(1/2))^(1/2)
或者在数学软件Mathematic中输入命令:
Roots[(x + 1) (x + 2) (x + 3) (x + 4) == (x + 1) (x + 1) + (x + 2) (
x + 2) + (x + 3) (x + 3) + (x + 4) (x + 4), x]
结果是
\!\(x == 1\/2\ \((\(-5\) - \[ImaginaryI]\ \@\(\(-13\) + 4\ \@15\))\) || x == \
1\/2\ \((\(-5\) + \[ImaginaryI]\ \@\(\(-13\) + 4\ \@15\))\) || x ==
1\/2\ \((\(-5\) - \@\(13 + 4\ \@15\))\) || x == 1\/2\ \((\(-5\) + \@\(13 \
+ 4\ \@15\))\)\)
或者输入:
Solve[(x + 1) (x + 2)(x + 3) (x + 4) == (x + 1) (x + 1) + (x + 2) (x + 2) + (
x + 3) (x + 3) + (x + 4) (x + 4), x]
结果是:
\!\({{x -> 1\/2\ \((\(-5\) - \[ImaginaryI]\ \@\(\(-13\) +
4\ \@15\))\)}, {x -> 1\/2\ \((\(-5\) + \[ImaginaryI]\ \@\(\(-13\
\) + 4\ \@15\))\)}, {x ->
1\/2\ \((\(-5\) - \@\(13 +
4\ \@15\))\)}, {x -> 1\/2\ \((\(-5\) + \@\(13 + 4\ \@15\))\)}}\)
由于Mathematic命令框内容非正常,实际结果与Matlab一样

x^4+10x^3+35x^2+50x+24 =4x^2+20x+30

x是复数解。。

开出括号生算
也可用字母代换各项

看了我都头晕!