手机百度一下怎么删除:(x+y)2-4(x+y-1)
来源:百度文库 编辑:查人人中国名人网 时间:2024/04/28 14:25:07
帮我解一下这题因式分解,谢谢
(x+y)^2-4(x+y-1)
=(x+y)^2-4(x+y)+4
=(x+y-2)^2
=(x+y)^2-(4x+4y-4)
=(x+y)^2-4(x+y)+2^2
=[(x+y)-2]^2
(x+y)2-4(x+y-1)
=(x+y)2-4(x+y)+4
=-2(x+y)+4
不知道这是不是你想要的答案
原式=4-2(x+y)=(2-根号2(x+y))*(2+根号2(x+y))
(x+y)^2-4(x+y-1)
=(x+y)^2-4(x+y)+4
=(x+y-2)^2
(^2表示平方)
(x+y)2-4(x+y-1)
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