沿月棹歌还的棹怎么读:已知cos(α+π/4)=3/5,π/2小于等于α<3π/2,求cos(2α+π/4)

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∵π/2≤α<3π/2,∴3π/4≤α+π/4<7π/4,又cos(α+π/4)=3/5>0,∴3π/2<α+π/4<7π/4,sin(α+π/4)=-√{1-[cos(α+π/4)]^2}=-4/5
∴sin2(α+π/4)=2sin(α+π/4)cos(α+π/4)=-24/25,cos2(α+π/4)=[cos(α+π/4)]^2-[sin(α+π/4)]^2=-7/25
cos(2α+π/4)=cos(2α+π/2-π/4)=cos2(α+π/4)cosπ/4+sin2(α+π/4)sinπ/4=(-7/25)*√2/2+(-24/25)*)*√2/2=-31√2/50