指甲剪得太短指甲疼:asp+a-jax简单问题

一段A-JAX代码
<script type="text/javascript" language="javascript">
var http_request = false;
function makeRequest(url) {
http_request = false;
if (window.XMLHttpRequest) { // Mozilla, Safari,...
http_request = new XMLHttpRequest();
if(http_request.overrideMimeType){
http_request.overrideMimeType('text/xml');
}
} else if (window.ActiveXObject) { // IE
try {
http_request = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try {
http_request = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e) {}
}
}
if (!http_request) {
alert('Giving up Cannot create an XMLHTTP instance');
return false;
}
http_request.onreadystatechange = alertContents;
http_request.open('GET', url, true);
http_request.send(null);
}
function alertContents() {
if (http_request.readyState == 4) {
if (http_request.status == 200) {
alert(http_request.responseText);
} else {
alert('There was a problem with the request.');
}
}
}
</script>

<input type="button" name="check" value="唯一性检查" onClick="makeRequest('test1.asp?email='+regedituser.email.value)" />

相应的TEXT1.ASP
<!--#include virtual="/Connections/conn.asp" -->
<%
Dim basicuser
Set basicuser = Server.CreateObject("ADODB.Recordset")
basicuser.ActiveConnection = MM_conn_STRING
basicuser.Source = "SELECT * FROM dbo.Basic_User WHERE email = '"&request("email")&"'"
basicuser.CursorType = 0
basicuser.CursorLocation = 3
basicuser.LockType =1
basicuser.Open()

if basicuser.recordcount=1 then
response.Write "用户名重复"
else
response.Write "可以使用“"&request("email")&"”为用户名"
end if
%>

问题所在

1、这是一个验证用户名是否重复的程序，其中第一点击按钮可以用，但是第二次不论正确与否都现实和第一次一样的弹出对话框
2、无法现实ASP页面的汉字 只能现实字母和数字

求高手指教
另附20问题 ： 哪位有好的关于A-JAX电子书求教电子邮件 woaie@126.com

先谢过，保证加分！
汉字无法显示是指返回的无法显示汉字

谢谢一楼

但是哪位有汉语版本的