originpro拟合两条曲线:x^4+y^4+z^4-(2x^2y^2)-(2x^2z^2)-(2y^2z^2)
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是因式分解吗?
x^4+y^4+z^4-(2x^2y^2)-(2x^2z^2)-(2y^2z^2)
x^4+y^4+z^4-2x^2y^2-2x^2z^2+2y^2z^2-4y^2z^2
(x^2-y^2-z^2)^2-4y^2z^2
(x^2-y^2-z^2+2yz)(x^2-y^2-z^2-2yz)
(x+y+z)(x+y-z)(x+z-y)(x-y-z)
已知3x-z=x+y+z=4x+2y-z,求x : y : z
x =2y,3y=4z,则x:y:z =?:?:?
2x+Y+3z=23,x+4y+5z=36,求X+2Y+3z~~~~
X+Y+Z=6 X-3Y+2Z=1 3X+2Y-Z=4
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
13x+5y+9z=12.7 2x+4y+3z=4.7 x+y+z=?
若x,y ,z满足方程组1、3x+7y-x=3 2、4x+10y-z=2 求X+Y+Z的值
(x+y)2-4(x+y-1)
(5x+4y-2z)(5x-4y-2z)=?