美女的小鸡放视频:1/(1*3)+1/(3*5) ........+1/(99*101)
来源:百度文库 编辑:查人人中国名人网 时间:2024/05/08 10:52:17
我要过程
1/n*(n+2)=1/2n-1/2(n+2),所以原式=0.5{1-1/3+1/3-1/5~~~~~~-1/101}=100/202
1/(1*3)+1/(3*5) ........+1/(99*101)
=1/2*(1-1/3)+2*(1/3-1/5).....+2*(1/99-1/101)
=1/2*(1-1/3+1/3-1/5+1/5-1/7......-1/99+1/99-1/101)
=1/2*(1-1/101)
=100/202
(1/2005-1)(1/2004-1)........(1/3-1)(1/2-1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
1+1/1+2+1/1+2+3+......+1/1+2+3+......+10
1/1+1/2+1/3+1/4+。。。。+1/N 是多少
1/3=??????
(1-1/2)*(1+1/2)*(1-1/3)*(1+1/3)*……*(1-1/99)*(1+1/99)。
(1+1/2)*(1-1/2)(1+1/3)*(1-1/3)*.......(1+1/99))*(1-1/99)怎么做
s=1/1+1/1!+1/2!+1/3!+1/4!+....+1/25!
1/1*2+1/2*3+1/3*4+...+1/2000*2001
1/(1*2)+1/(2*3)+1/(3*4)+..+1/(99*100)