碘和硫代硫酸钠:1/2(A^2+B^2+C^2)-BC-CA-AB因式分解
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=1/2(a+b+c)^2
题目有没有错?
化简:(2a-b-c)/(a-b)(a-c)+(2b-c-a)/(b-c)(b-a)+(2c-a-b)/(c-a)(c-b)
2a-b-c/(a-b)(a-c)+ab -c-a/(b-c)(b-a)+2c-a-b/(c-a)(c-b)
b/(a+b)=(a+c+-b)/(b+c-a)=(a+b+c)/(2a+b+2c)求a:b:c=
化简:(a+b)^2(b+c-a)(c+a - b)+(a - b)^2(a+b+c)(a+b - c)
(a-b+c)^2
(a+b)/c=(a+c)/b=(b+c)/a =2(a+b+c)/
a+b+c<6 a,b,c>0 证a/(a^2-1)+b/(b^2-1)+c/(c^2-1)>2
a+1/b=b+1/c=c+1/a 且 a b c 互不相等,求:a^2b^2c^2
答题!!!!!!!!!!!!!!!!!!!!2(a*a*a-3)(a-b+c)-3(b-a*a)(a+b-c)
求证a^2/(b+c-a)+b^2/(a+c-b)+c^2/(a+b-c)=>a+b+c