日语家教兼职阜新:解方程:4(sin^6 x+cos^6 x)=1,x∈[0.pi/2]
来源:百度文库 编辑:查人人中国名人网 时间:2024/04/29 23:38:22
sin^6 x+cos^6 x=1/4
(sin^2 x)^3+(cos^2 x)^3=1/4
(sin^2 x +cos^2 x)(sin^4 x -sin^2 x*cos^2 x+cos^4 x)=1/4
(sin^2 x-cos^2 x)^2+sin^2 x*cos^2 x=1/4
cos^2 2x +(sin^2 2x)/4=1/4
1/4+3/4*cos^2 2x=1/4
所以 cos2x=0
又2x∈[0,pi]
所以,2x=pi/2
=> x=pi/4
解方程:4(sin^6 x+cos^6 x)=1,x∈[0.pi/2]
解方程:4(sin^6 x+cos^6 x)=1,x∈[0.pi/2].
解方程sin^2x-7sinxcosx+6cos^2x=0
cos(2x)+6sin^2(x/2)-8sin^4(x/2)=?
已知(4sin^2) x-(cos^2)x-6sinx+3cosx=0,求(cos2x-cos^2 x)/(1-cot^2 x)的值
已知(4sin^2) x-(cos^2)x-6sinx+3cosx=0,求(cos2x-cos^2 x)/(1-cot^2 x)的值
已知(4sin^2) x-(cos^2)x-6sinx+3cosx=0,求(cos2x-cos^2 x)/(1-cot^2 x)的值。
已知(4sin^2) x-(cos^2)x-6sinx+3cosx=0,求(cos2x-cos^2 x)/(1-cot^2 x)的值。
COS ( PAI/4-X)*COS(PAI/4 X)=跟号2/6 则SIN 2X的值是?
求值: 1-sin^6a-cos^6a/1-sin^4a-cos^4a