车载音乐视频免费下载:1 2 3 4 5 6 7 8 9这九个数字用加减乘除或括号(其他不可以用)怎么算出得1?

来源:百度文库 编辑:查人人中国名人网 时间:2024/04/29 07:39:36
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1*(3-2)*(5-4)*(7-6)*(9-8)=1
1+(3-2)-(5-4)+(7-6)-(9-8)=1
1*(3-2)/(5-4)/(7-6)*(9-8)=1
1/(3-2)*(5-4)*(7-6)*(9-8)=1
1*(3-2)*(5-4)*(7-6)/(9-8)=1
1*(3-2)*(5-4)/(7-6)*(9-8)=1

1*(3-2)*(5-4)*(7-6)*(9-8)=1
1+(3-2)-(5-4)+(7-6)-(9-8)=1
1*(3-2)/(5-4)/(7-6)*(9-8)=1
1/(3-2)*(5-4)*(7-6)*(9-8)=1
1*(3-2)*(5-4)*(7-6)/(9-8)=1
1*(3-2)*(5-4)/(7-6)*(9-8)=1
其实办法多得很,就是上面的加减乘除的调换而已

方式多样:
(9-8)-(7-6)+(5-4)-(3-2)+1=1
1*(3-2)*(5-4)*(7-6)*(9-8)=1
..........

1*(3-2)*(5-4)*(7-6)*(9-8)=1
1/(3-2)*(5-4)*(7-6)*(9-8)=1
1*(3-2)*(5-4)*(7-6)/(9-8)=1
1*(3-2)*(5-4)/(7-6)*(9-8)=1
1+(3-2)-(5-4)+(7-6)-(9-8)=1
1*(3-2)/(5-4)/(7-6)*(9-8)=1

1+2+3+4-5+6+7-8-9=1
即:(1+2+3+4+6+7)-(5+8+9)
=23-22
=1

1*(3-2)*(5-4)*(7-6)*(9-8)=1
1+(3-2)-(5-4)+(7-6)-(9-8)=1
1*(3-2)/(5-4)/(7-6)*(9-8)=1
1/(3-2)*(5-4)*(7-6)*(9-8)=1
1*(3-2)*(5-4)*(7-6)/(9-8)=1
1*(3-2)*(5-4)/(7-6)*(9-8)=1