1688一键铺货:若(x+1)(y-1)=1,x2y+xy2=-1 ,则(x2+y2)(x3-y3)=

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(x+1)(y-1)=1 推出xy-(x-y)=2
x2y+xy2=-1 推出：xy(x+y)=-1
(x2+y2)(x3-y3)=

因为（x-y)的平方等于x2+y2-2xy=3-2*1=1 所以 x-y = 1

x2是x的平方？

(xy+1)(x+1)(y+1)+xy 因式分解xy-x-y+1 若(x+1)(y-1)=1,x2y+xy2=-1 ,则(x2+y2)(x3-y3)= 若x+y=3,xy=1,则(-5x+2)-(3xy+5y)等于多少 若x>y,且xy=1，求(x^2+y^2)/(x-y)的最小值 已知x-y=11求(xy-1)的平方＋(x+y-2)×(x+y-2xy)的值 1.若1/x-1/y=3,则分式2x+3xy-2y/x-2xy-y 的值为多少? x2+4xy+y2-2x-4y+2=0,求x2y+y2x=? 因式分解（x+y)*(x+y+2xy)+(xy+1)*(xy-1) x, y>0。求证x/y+y/x+xy>x+y+1