中国几大菜系排名第一:php4 连接数据库问题???

来源：百度文库编辑：查人人中国名人网时间：2024/04/27 13:33:06

原文件是这样的！
<html>
<head>
<title>Select Admin</title>
</head>
<body>
<?php
$db = mysql_connect("localhost", "ff","ff");
mysql_select_db("mydatabase",$db);
$result = mysql_query("SELECT * FROM t_admin",$db);
echo "< border=1>\n";
echo "<><>姓名</td><>密码</td></tr>\n";
while ($myrow = mysql_fetch_row($result)) {
printf("<><>%s %s</td><>%s</td></tr>\n", $myrow[1], $myrow[2], $myrow[3]);
}
echo "</table>\n";
?>
</body>
</html>
我的
mysql的版本是5.
用的是Apache HTTP Server Version 2.0
php的版本是4;
mysql数据库中有一个数据库名字叫mydatabase;
mysql数据库的用户名和密码都是,ff;
运行以上原文件后，出现如下的错误：

Warning: mysql_connect(): Client does not support authentication protocol requested by server; consider upgrading MySQL client in D:\www\index.php on line 7

Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in D:\www\index.php on line 8

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\www\index.php on line 9
< border=1> <><>姓名<>密码
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in D:\www\index.php on line 12
什么原因？

请高手指点！谢谢!
错误！
Warning: mysql_connect(): Client does not support authentication protocol requested by server; consider upgrading MySQL client in D:\www\index.php on line 7
Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in D:\www\index.php on line 8
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in D:\www\index.php on line 9
Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in D:\www\index.php on line 12
姓名密码

你PHP环境配好没，确认无误？

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