查人人中国名人网上海企业咨询公司排名:2005全国"希望杯"数学竞赛试题[一道英语数学题]
来源：百度文库 编辑：查人人中国名人网 时间：2024/05/01 13:08:46
是一道英语题
For-a-real-number-a,let[a]denote-the maximum-integer-which-does-not-exceed-a.For example,[3.1]=3,[-1.5]=-2,[0.7]=0.Now let
.....x+1
f(x)=—
.....x-1,then[f(2)]+[f(3)]+L+[f(100)]
(real-number:实数,the maximum-integer-which-does-not-exceed-a:不超过a的最大整数)
For-a-real-number-a,let[a]denote-the maximum-integer-which-does-not-exceed-a.For example,[3.1]=3,[-1.5]=-2,[0.7]=0.Now let
.....x+1
f(x)=—
.....x-1,then[f(2)]+[f(3)]+L+[f(100)]
(real-number:实数,the maximum-integer-which-does-not-exceed-a:不超过a的最大整数)
.....x+1
f(x)=— = 1+[2/(x-1)]
.....x-1
f(2)=1+2=3;
f(3)=1+2/2=2;
f(4)=1+2/3<2;
---------------------
[f(n)]=1; n>=4;
[f(2)]=3;
[f(3)]=2;
[f(2)]+[f(3)]+L+[f(100)]
=3+2+(100-2)
=103
通过[3.1]=3,[-1.5]=-2,[0.7]=0这个式子可以看出是取整问题,[]代表取一个数的整数数位,负数则要取比它小的整数.
但是.....x+1
f(x)=—
.....x-1,then[f(2)]+[f(3)]+L+[f(100)]
这个没看懂