prince2 2009 中文版:sinα=(2^0.5)sinβ,(3^0.5)cosα=(2^0.5)cosβ,求α、β的值

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sinα=(2^0.5)sinβ,(3^0.5)cosα=(2^0.5)cosβ,求α、β的值
0<α<π
0<β<π(派)

sinα = √2*sinβ .........................(1)
√3*cosα = √2*cosβ ...............(2)

3*(1)^2 + (2)^2 得:
3 = 6*(sinβ)^2 + 2*(cosβ)^2
(sinβ)^2 = 1/4 .................. β = π/6、2π/3

(1)^2 + (2)^2 得:

(sinα)^2 + 3(cosα)^2 = 2
(cosα)^2 = 1/2 .................. α = π/4、3π/4

综合得到 α = π/4、β = π/6