临海市现任领导班子:化简：2sin50°/sin100°＋tan10°

来源：百度文库 编辑：查人人中国名人网 时间：2024/05/05 09:41:22
这是一道高一年级的关于三角函数的化简题！

2sin50°/sin100°＋tan10°
=2sin50°/cos10°＋sin10°/cos10°
=(2sin50°+sin10°)/cos10°
=[2sin(60°-10°)+sin10°]/cos10°
=(√3cos10°-sin10°+sin10°)/cos10°
=√3

2sin50°/sin100°＋tan10°
=2sin50°/cos10°＋sin10°/cos10°
=(2sin50°+sin10°)/cos10°
=[2sin(60°-10°)+sin10°]/cos10°
=(√3cos10°-sin10°+sin10°)/cos10°
=√3

原式=2sin50/cos10+sin10/cos10
=[2sin60cos10-2cos60sin10+sin10]/cos10
=√3

=2sin50/cos10+sin10/cos10
=[2sin60cos10-2cos60sin10+sin10]/cos10
=√3

sin10°sin30°sin50°sin70°=? 化简：2sin50°/sin100°＋tan10° 化简：2sin50°/sin100°＋tan10° 化简：（根号1-2sin10°×cos10°）比sin10°-根号1-sin^210° 求值2sin20°+2cos20°+cos70°sin10°/sin70° 求值2sin20°+2cos20°+cos70°sin10°/sin70° 1/sin10°-(根号3)/cos10° 求(3/sin^2 140°-1/cos^2 140°)*1/(2sin10°) sin50°(1+cot80°) 化简√（1+Sin10º）+√（1-Sin10º)