来源：百度文库 编辑：查人人中国名人网 时间：2024/04/29 13:02:35
若x+y+z=0,则分解因式x^3+y^3+z^3=_____________
x^3+y^3+z^3
=x^3+y^3+(-x-y)^3
=x^3+y^3-(x+y)^3
=x^3+y^3-x^3-y^3-3x^2y-3xy^2
=-(3x^2*y+3y*x^2)
=-3xy(x+y)
=-3xy(-z)
=3xyz
x^3+y^3+z^3=(x+y+z)(x^+y^+z^-xy-yz-xz)+3xyz
=3xyz
3xy
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