哈尔滨唯美电脑学校:七年级数学题

来源:百度文库 编辑:查人人中国名人网 时间:2024/05/12 15:35:34
若1/x=2/x+z=3/y+z,则x/z-y=?

已知x2-4xy+4y2=0,那么分式x+y/x-y的值?
注:x2,y2指平方

thanks a lot!

1.
1/x=2/(x+z)
2x=x+z
x=z

1/x=3/(y+z)
3x=y+z
y=3x-z=2x

x/(z-y)=x/(x-2x)=-1

2.
x^2-4xy+4y^2=0
(x-2y)^2=0
x=2y
(x+y)/(x-y)=(2y+y)/(2y-y)=3

1.
设1/x=2/(x+z)=3/(y+z)=1/k
则x/1=(x+z)/2=(y+z)/3=k
x=k,z=k,y=2k.
x/(z-y)=k/(k-2k)=-1.

2.x2-4xy+4y2=(x-2y)^2=0
x=2y

(x+y)/(x-y)=(2y+y)/(2y-y)=3

1.
1/x=2/(x+z)
2x=x+z
x=z

1/x=3/(y+z)
3x=y+z
y=3x-z=2x

x/(z-y)=x/(x-2x)=-1

2.
x^2-4xy+4y^2=0
(x-2y)^2=0
x=2y
(x+y)/(x-y)=(2y+y)/(2y-y)=3

1题:左右分别化简单:xz=-1
2y=3x 后面x/z-y是什么意思?
分母是z?还是Z-Y?

2题:x2-4xy+4y2=0 解得x=2y 所以x+y/x-y=3y/y=3