疯狂的僵尸破解版:一道数学题 急用

来源:百度文库 编辑:查人人中国名人网 时间:2024/05/12 18:58:36
计算:
(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3 (要步骤)

(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3
=(-2)^2X^6+(-3)^3X^6+2^3X^3*(-1)^3X^3
=4X^6-27X^6-8X^6
=-31X^6

(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3
=4x^6-27x^6-8x^6
=-31x^6

(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3
=(-2)^2X^6+(-3)^3X^6+2^3X^3*(-1)^3X^3
=4X^6-27X^6-8X^6
=-31X^6

(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3
=(-2)^2X^6+(-3)^3X^6+2^3X^3*(-1)^3X^3
=4X^6-27X^6-8X^6
=-31X^6

(-2x^3)^2+(-3x^2)^3+(2x)^3*(-x)^3
=4x^6+(-27x^6)+8x^3*(-x^3)
=4x^6-27x^6-8x^6
=-31x^6